m^2=4/169

Solution for m^2=4/169 equation:

m^2=4/169

We move all terms to the left:

m^2-(4/169)=0

We add all the numbers together, and all the variables

m^2-(+4/169)=0

We get rid of parentheses

m^2-4/169=0

We multiply all the terms by the denominator


m^2*169-4=0

Wy multiply elements

169m^2-4=0

a = 169; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·169·(-4)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52}{2*169}=\frac{-52}{338}
=-2/13
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52}{2*169}=\frac{52}{338}
=2/13
$